Question

a piece of wire 60 cm long is cut into two pieces the shortest of which must be at least 6 cm long. One piece is to be bent into the shape of an equilateral triangle and the other is bent into the shape of a rectangle which is twice as long as it is wide. Find the maximum and minimum for the sum of areas enclosed by the two pieces of wire

Answer 1

Now we can write certain equations:
6x + 3y = 60 ----> 2x + y = 20
6x >6 -------> x > 1
3y> 6 ---------> y > 2

TotalArea = 2x^2 + sqrt(3)/4y^2