Question

Does anyone want to help me out with a few log questions?

Answer 1

What's the question?

Answer 2

\[(4/7)^x=6^1-x \] @Ankh

Answer 3

6 to the power of 1?

Answer 4

thats what it says lol but solve for x

Answer 5

oh wait its 6^(1-x)

Answer 6

Well I reached a simpler form, but not sure how to continue from there, it's quite a challenging problem.

Answer 7

Oh wait I think i solved it.

Answer 8

okay thanks, i just needed to find it in decimal form bc its multiple choice

Answer 9

did u get..\[\ln6/\ln(4/7)+\ln6\]

Answer 10

\[\left( \frac{ 4 }{ 7 } \right)^x=6^{x-1}\]
\[\frac{ 4^x }{ 7^x } = 6^1 \times 6^{-x}\]
\[\frac{ 4^x }{ 7^x } = \frac{ 6 }{ 6^x }\]
\[4^x \times 6^x = 7^x \times 6\]
\[\frac{ 24^x }{ 7^x } = 6\]
\[\log_{24/7} (6)=x\]

Answer 11

okay thank you, i get it now!