Question

Use natural logarithms to solve the equation.

5e^(2x+11)=30

Answer 1

hit both sides with a log.

Answer 2

with a natural log.

Answer 3

try....please.

Answer 4

Lol "hit"

Answer 5

Alright hold on :P

Answer 6

I remember my trigonometry teacher, (a quite knowledgeable man in math and science) called that "hitting with a log".

Answer 7

take your time, priest.

Answer 8

Oh no Zelman, we have to do something first before hitting both sides with a log.

Answer 9

yes, true, lol

Answer 10

Divide both sides by 5.

Answer 11

Not what I meant..

Answer 12

stop trying to confuse me, I already suck at math.

Answer 13

Yes, go ahead and divide both side by 5.

Answer 14

You can actually do it either way, so long as you know the properties of logs.

It's just that division is a lower order operation than log, so dividing first is simpler.

Answer 15

e^(2x+11)=6
:P

Answer 16

yes

Answer 17

now take the \(\large\color{black}{ \ln }\) of both sides.

Answer 18

I love a neater way, if you are gonna do logarithms first, you can take the log (base 5) of both sides.

Answer 19

or you can apply a rule:
\(\large\color{black}{ a=e^{\ln a} }\)

Answer 20

2x + 11 = ln 6.... Do I just subtract the 11?

Answer 21

yes, you are getting it right.
2x+11=ln(6).

Answer 22

and yes again, subtract 11 from both sides.

Answer 23

2x = ln (-5)
Divide 2 from both sides...
x = ln(-5)/2