Question

Triangle Proofs Will give fan and medal

Answer 1

@ganeshie8 @Hero @SolomonZelman

Answer 2

@dumbcow @cwrw238

Answer 3

@wio @satellite73 @nincompoop

Answer 4

@wio @dumbcow can you guys help?

Answer 5

Those reflexive property lines aren't doing anything.

Answer 6

Then what would I have to do?

Answer 7

what is side side side similarity theorem?

Answer 8

Like the definition?

Answer 9

If the sides of one triangle are proportional to the sides of a second triangle, then the triangles are similar.

Answer 10

It's an if and only if statement?

Answer 11

Thats the definition that I have on my lesson

Answer 12

Well, the converse is true, right?

Answer 13

yes

Answer 14

But from what is written, we can't assume the converse is true.

Answer 15

okay so What can we do to prove it then

Answer 16

What other theorems do you have?

Answer 17

SAS, SSS, Triangle Proportionality Theorem, Converse of Triangle Proportionality Theorem, Pythagorean Theorem, Converse of the Pythagorean Theorem, Angle-Angle theorem

Answer 18

Mainlyjust all the theorems to go along with proofs

Answer 19

What is: Converse of Triangle Proportionality Theorem

Answer 20

If a line divides any two sides of a triangle proportionally, then the line must be parallel to the third side.

Answer 21

Wait, so there is a Converse of the SSS similarity theorem?

Answer 22

I havent heard of it

Answer 23

It's at the bottom of the text box

Answer 24

oh okay, I will look for it

Answer 25

I suppose its if the triangles are similar then the sides of two triangles are in proportion?

Answer 26

I could help better if I knew the theorems you are allowed to use, but I don't know them yet.

Answer 27

I can try to find someone else if you'd like

Answer 28

Hmm, well, I'm just wondering if you're allowed to use the converse of sss similarity

Answer 29

We are allowed to use it. I can still try to find someone else if you dont understand it

Answer 30

\[
\begin{array}{c|l}
\angle B\cong \angle D & \text{Given} \\
\angle A\cong \angle E & \text{Given} \\
\triangle ABC\sim \triangle DEF & \text{Angle-Angle Similarity Theorem}\\
AB= k ED &\text{Converse of Side-Side-Side Similarity Theorem}\\
\frac{AB}{ED}= k &\text{Division property of equality}\\
BC = k DF &\text{Converse of Side-Side-Side Similarity Theorem}\\
\frac{BC}{DF}= k &\text{Division property of equality}\\
\frac{AB}{ED}= \frac{BC}{DF} &\text{Transitive property of equality}\\
\end{array}
\]

Answer 31

I'm not sure how they expect you to denote proportionality

Answer 32

Thank you very much for all of your help, I highly appreciate it

Answer 33

What does k stand for?

Answer 34

But I denote proportionality for \(a\) and \(b\) as meaning there is a \(k\) where: \[
a = kb
\]

Answer 35

oh okay

Answer 36

I wrote it this way because I don't know the way they expect it to be writen