Algebra
9 Online
OpenStudy (anonymous):
What is an equivalent form of
3
-----
4-2i
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OpenStudy (danjs):
I think you need to multiply top and bottom by 4+2i
OpenStudy (anonymous):
oh ok
OpenStudy (danjs):
u have it from there?
OpenStudy (anonymous):
doesn't it cancel?
OpenStudy (nincompoop):
it doesn't
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OpenStudy (danjs):
use i^2 = -1
OpenStudy (anonymous):
oohh ok
OpenStudy (nincompoop):
multiplying by the conjugate doesn't necessarily cancel unless there is something to cancel.
OpenStudy (anonymous):
hmmm
OpenStudy (danjs):
3/(4-2i) = (12 + 6i)/ (16 +4i^2)
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OpenStudy (danjs):
i^2=-1
OpenStudy (anonymous):
i see, so i becomes -1 regardless. and the answer is that equation?
OpenStudy (danjs):
put in -1 for i^2 and simplify the denominator
OpenStudy (anonymous):
because it doesn't tell me to solve it
OpenStudy (anonymous):
ok i get it
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OpenStudy (danjs):
(12+6i)/)(16-4)
OpenStudy (anonymous):
-18/12
OpenStudy (anonymous):
?
OpenStudy (danjs):
It is the same as though you are using normal variables, just recall that i^2=-1 in your final answer
OpenStudy (anonymous):
Ok thank you!!
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OpenStudy (danjs):
no the numorator has just i in it, you have to leave that alone
OpenStudy (danjs):
(12+6i)/12
OpenStudy (danjs):
now you can factor a 6 out of top and bottom
OpenStudy (danjs):
[6(2+i)] / (6*2)
cancel the 6's
OpenStudy (danjs):
(2+i) / 2
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OpenStudy (anonymous):
wow, you are awesome thank you
OpenStudy (danjs):
np, anytime