Question

Algebra 2

Answer 1

\[\frac{ \sqrt 2 - \sqrt 6 }{ \sqrt 2 + \sqrt 6 }\]

Answer 2

if you want a rational denominator multiply by the conjugate which is the same as multiplying by 1, its just written in another form.

\[\frac{\sqrt{2} - \sqrt{6}}{\sqrt{2} + \sqrt{6}} \times \frac{\sqrt{2} - \sqrt{6}}{\sqrt{2} - \sqrt{6}}\]

you should notice the denominator is now the difference of 2 squares

hope it helps

Answer 3

This is still confusing......

Answer 4

wait...I think I got it... uno momento

Answer 5

using what campbell said earlier when you multiply the two you end up with this

\[ \frac{ (2 - \sqrt{12} - \sqrt{12} - 6 ) }{ (2 - 6) }\]

Answer 6

okay.....

Answer 7

so \(-4- 2 \sqrt 12\) on the top, right??

Answer 8

correct....

Answer 9

okay great.

Answer 10

How can we simplify that?

Answer 11

so you have

\[\frac{-4 -2\sqrt{12}}{2 - 6}\]

so simplify the denominator and the remove a common factor

Answer 12

\(\Large\frac{-4 -2\sqrt{12}}{- 4}\) so wouldn't the common factor be -2? I don't get how to simplify this stuf...

Answer 13

whoopsies! stuff*

Answer 14

that'c correct so it becomes

\[\frac{ 2 + \sqrt{12}}{2}\]

the last step is knowing 12 = 4 x 3

\[\sqrt{12} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}\]

so make the substitution and look for a common factor

Answer 15

okay.....2 is the common factor would be 2, right? I'm super confused still :/ Normally math is easier for me but not right now

Answer 16

whoopsies, I repeated myself without even knowing it :P heehee

Answer 17

This is the whole question....I'm not sure what it is :/