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Mathematics 8 Online
OpenStudy (anonymous):

Solve the triangle. A = 32°, a = 19, b = 14

OpenStudy (anonymous):

32 degres

OpenStudy (catlover5925):

\(\huge\scr\color{magenta}{May~I~Help??}\)

OpenStudy (anonymous):

Yes please :)

OpenStudy (catlover5925):

you need to use the pothagoren therom which is \(\small\color{red}{a^2~+~b^2~=~c^2}\)

OpenStudy (anonymous):

19^2 +14^2

OpenStudy (anonymous):

B is 23 degrees

OpenStudy (catlover5925):

actually it is 23.60 so you would round to 24

OpenStudy (catlover5925):

\(\huge\color{lime}{Good~Work!}\)

OpenStudy (anonymous):

Under my answer options it shows 23

OpenStudy (anonymous):

B = 23°, C = 125°, c ≈ 17.6 Cannot be solved B = 23°, C = 125°, c ≈ 29.4 B = 23°, C = 145°, c ≈ 23.5 @Catlover5925

OpenStudy (anonymous):

the question marks mean degres @Catlover5925

OpenStudy (catlover5925):

your computer is lagging if you refresh you can see the degrees signs but then yes i would choose 23

OpenStudy (anonymous):

I dont know how to find the other parts

OpenStudy (anonymous):

@Catlover5925

OpenStudy (anonymous):

I already knew how to find B just not the others

OpenStudy (catlover5925):

ok i dont understand ur question the way you posted it are you trying to find the third degree??

OpenStudy (anonymous):

solve the triangle

OpenStudy (anonymous):

I need B,C,c

OpenStudy (anonymous):

@Catlover5925

OpenStudy (catlover5925):

i dont know what that is but |dw:1418776943566:dw| on the second one is this what you are trying to find??

OpenStudy (anonymous):

I realy dont know

OpenStudy (anonymous):

@amistre64 @mathstudent55 Do either of you know where to go from here ?

OpenStudy (anonymous):

@Compassionate @wio Can you please help

OpenStudy (anonymous):

You can only use Pythagorean theorem for right triangles.

OpenStudy (anonymous):

Can you draw the triangle first?

OpenStudy (anonymous):

|dw:1418778754509:dw|

OpenStudy (anonymous):

|dw:1418778785103:dw|

OpenStudy (anonymous):

First step is to use the law of sines: \[ \frac{\sin(32^\circ)}{19} = \frac{\sin(B)}{14} \]

OpenStudy (anonymous):

Next step, remember that the angles add up to \(180^\circ\), so that means:\[ C= 180^\circ -(A+B) \]

OpenStudy (anonymous):

Then use law of sines again to solve for \(c\).

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