Solve the triangle. A = 32°, a = 19, b = 14
32 degres
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Yes please :)
you need to use the pothagoren therom which is \(\small\color{red}{a^2~+~b^2~=~c^2}\)
19^2 +14^2
B is 23 degrees
actually it is 23.60 so you would round to 24
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Under my answer options it shows 23
B = 23°, C = 125°, c ≈ 17.6 Cannot be solved B = 23°, C = 125°, c ≈ 29.4 B = 23°, C = 145°, c ≈ 23.5 @Catlover5925
the question marks mean degres @Catlover5925
your computer is lagging if you refresh you can see the degrees signs but then yes i would choose 23
I dont know how to find the other parts
@Catlover5925
I already knew how to find B just not the others
ok i dont understand ur question the way you posted it are you trying to find the third degree??
solve the triangle
I need B,C,c
@Catlover5925
i dont know what that is but |dw:1418776943566:dw| on the second one is this what you are trying to find??
I realy dont know
@amistre64 @mathstudent55 Do either of you know where to go from here ?
@Compassionate @wio Can you please help
You can only use Pythagorean theorem for right triangles.
Can you draw the triangle first?
|dw:1418778754509:dw|
|dw:1418778785103:dw|
First step is to use the law of sines: \[ \frac{\sin(32^\circ)}{19} = \frac{\sin(B)}{14} \]
Next step, remember that the angles add up to \(180^\circ\), so that means:\[ C= 180^\circ -(A+B) \]
Then use law of sines again to solve for \(c\).
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