Determine whether the given binomial is a factor of the polynomial (x+5): p(x)=2x^2-6x-1 (X-6); P(x)= -2x^2+15x-18 (x+3); P(x)= 2x^2-x+7
in order to factor a binomial you have to know that the discriminant is a perfect square.
what is the discriminant of \(\large\color{black}{ p(x)=2x^2-6x-1 }\) ?
hey, do you know what a discriminant is and how to find it? you don't seem to understand what I said.... and if you don't get what I said, ask ...
you can divide (for example) \(\large\color{black}{ 2x^2-6x-1 }\) by \(\large\color{black}{ x+5 }\)
and see if you have a remainder then x+5 is NOT a factor, if no remainder, then x+5 is a factor.
I would like to verify your answers once you are done, please.
and my suggestion is just the discriminant for the 1st and 3rd, and polynomial or synthetic division for the second.
the easiest method is to use the factor theorem if (x- a) is a factor then x = a is a zero so find p(a)... so if p(a) = 0 then a is a zero and (x - a) is a factor in the 1st question (x +5) is a factor... so x = -5 is a factor find p(-5) if its equal to zero then (x + 5) is a factor, otherwise it's not hope it helps
so \[p(-5) = 2 \times (-5)^2 -6 \times (-5) - 1\] just calculate the value if it's zero, then (x + 5) is a factor
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