Question

Can anyone possibly help me with the rest of this AP Calc BC problem? (I shall post a picture)

Answer 1

i assume you need help with #3?

Answer 2

Yes part c please :)

Answer 3

Meow

Answer 4

there it is :)

Answer 5

what do you know about calculus and finding the slope at a given point to a function?

Answer 6

i see it written there as g'(x) = f(t)

Answer 7

g'(2) is the slope of the line at the point 2,g(2)

so all we really need to know is what g'(2) is and what g(2) is

Answer 8

I believe what I just did
i got g(2) = 2 + pi and g'(2) =1

Answer 9

those look good to me

so out slope is 1, and our point is 2,2+pi

how do we form the equation of a line if we know the slope and a point?

Answer 10

Oh alright duh lol

Answer 11

:)

Answer 12

y-2=1(x-2+pi) lol

Answer 13

almost, xo = 2, yo = 2+pi

but yeah

y - (2+pi) = 1(x-2)

Answer 14

simplify to your hearts content

Answer 15

for part d, take the derivative of g' and determine where it is 0 or undefined at

Answer 16

I believe inflection points are where the graph of f changes concavity. So AKA when the slope of f'(t) is increasing/decreasing so I just have to find that

Answer 17

slope of a straight line is 0, slope of a slanted line is its slope, and slope of a circle is 0 or undefined at the top and sides

Answer 18

Yeah that I know

Answer 19

might be tricky at the cusps, and im not sure, but i think a straight line has no inflection points, so the only one that may be doable is the top of the arc there

Answer 20

Well

g'(t) = f(t)

so g''(t) = f'(t) and f'(t) are the points on the graph

Answer 21

f'(t) is the slope of the curves on the graph

Answer 22

in other words, the graph as is tells us the slope of g at any given point;

the slope of the slope tells us about concavity

Answer 23

I know and the points on the graph show us f'(t) and how the slope is changing

I'll talk to my teacher tomorrow about my answer. Thanks for your help though today! I appreciate it!

Answer 24

good luck ;)

Answer 25

Thanks!