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Mathematics 17 Online
OpenStudy (anonymous):

Cramming for finals, please help!! 1.) Formula A=P(1+r/n)^nt to find the total amount of money accumulated at the of the time given. $1400 for 8 years at 7% compounded quarterly 2.) Same formula; $200 for 5 years at 5% compounded annually. 3.) Suppose that the cost for producing a certain item is C(n)=4n-6 where n is the number of items produced. Compute C(200), C(500), C(650), and C(1300)

OpenStudy (danjs):

so n here would be quarterly

OpenStudy (danjs):

or 4

OpenStudy (danjs):

P = 1400 t = 8 n = 4

OpenStudy (anonymous):

wait for the first one wouldnt r=.07 ?

OpenStudy (danjs):

yeah, sorry

OpenStudy (danjs):

if something is compounded quarterly, does that mean n=4 or n=1/4?

OpenStudy (anonymous):

okay so would the formula look like this: \[A= 1400(1+\frac{ 0.07 }{ 4 }^{4(0.07)}\]

OpenStudy (danjs):

ok yeah i just looked it up, n=4 is the number of times compounded per year

OpenStudy (danjs):

so that is the correct formula to solve

OpenStudy (danjs):

except, the exponent is n*t which is 4*8

OpenStudy (anonymous):

oh okay

OpenStudy (danjs):

\[1400(1+\frac{ 0.07 }{ 4 })^{^{4*8}}\]

OpenStudy (danjs):

i get 2439.1 about

OpenStudy (danjs):

for part B) n = 1 P=200 t=5 r=0.05

OpenStudy (anonymous):

Okay that's what I got too.

OpenStudy (anonymous):

for the second one i got 255.26 about

OpenStudy (anonymous):

@DanJS

OpenStudy (danjs):

um

OpenStudy (danjs):

yeah same here

OpenStudy (anonymous):

Do you know how I'd do the 3rd one? @DanJS @iambatman

OpenStudy (danjs):

yeah just put in those 4 different numbers for n

OpenStudy (danjs):

C(n) = 4n-6

OpenStudy (anonymous):

Oh okay lol sorry

OpenStudy (anonymous):

@DanJS it says our answer for the first one is wrong

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