Question

help with algebra 2?

Answer 1

@perl

Answer 2

What it simply asks you is to divide \(x^4-9x^3-5x^2-3x+4\) by \(x+3\)

Answer 3

And what is given out is the answer. The reason it says the remainder theorem means there will be a remainder

Answer 4

Do you know how to do that?

Answer 5

P(x) = (x + 3)Q(x) + R

=> P(-3) = (0)Q(x) + R

i.e. P(-3) = R

Now, P(-3) = (-3)⁴ - 9(-3)³ - 5(-3)² - 3(-3) + 4

so, P(-3) = 81 + 243 - 45 + 9 + 4

i.e. 292

Answer 6

I got this but I dont get it

Answer 7

Here is the thing, you don't know that x=3. How did you get that?

Answer 8

It simply says x-3, not x-3=0. Since it doesn't equal to anything, you can't say x=3. x-3 is simply a factor of that equation. Divide the big equation with x-3, and you will get the answer

Answer 9

You would need to either use a calculator, or long division in a test

Answer 10

Nello are you taking Algebra 2 at Connections Academy? (Connexus)