Question

What's the quadratic formula?

Answer 1

http://www.purplemath.com/modules/quadform.htm

Answer 2

@hockeychick23 that is the standard form of a quadratic equation, not the quadratic formula

Answer 3

\(ax^2+bx+c=0\\
ax^2+bx+c+\frac{b^2}{a2^2}-\frac{b^2}{a2^2}=0
\\ax^2+bx+\frac{b^2}{a2^2}+c-\frac{b^2}{a2^2}=0
\\ax^2+\frac{b}{2}x+\frac{b}{2}x+\frac{b^2}{2^2a}+c-\frac{b^2}{2^2a}=0\\
ax^2+\frac{bx}{2}+\frac{bx}{2}+\frac{b^2}{2^2a}+c-\frac{b^2}{2^2a}=0\\
a(x^2+\frac{bx}{2a}+\frac{bx}{2a}+\frac{b^2}{2^2a^2})+c-\frac{b^2}{2^2a}=0\\
a(x+\frac{b}{2a})^2+c-\frac{b^2}{2^2a}=0\\
a(x+\frac{b}{2a})^2=\frac{b^2}{2^2a}-c\\
a(x+\frac{b}{2a})^2=\frac{b^2}{2^2a}-\frac{c2^2a}{2^2a} \\
a(x+\frac{b}{2a})^2=\frac{b^2-4ac}{2^2a}\\
(x+\frac{b}{2a})^2=\frac{b^2-4ac}{2^2a^2}\\
(x+\frac{b}{2a})=\pm \sqrt{\frac{b^2-4ac}{2^2a^2}}\\
(x+\frac{b}{2a})=\pm \sqrt{\frac{b^2-4ac}{2^2a^2}}\\
(x+\frac{b}{2a})=\pm \frac{\sqrt{b^2-4ac}}{2a}\\
x=\pm \frac{\sqrt{b^2-4ac}}{2a}-\frac{b}{2a}\\
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\





\)

the one at the end

Answer 4

what is google?

Answer 5

Thanks