Question

M is the midpoint of RS. R is at (4,3) and M is at (6,7). What are the coordinates of S?

Answer 1

from 4 to 6 is two units right
go another two and get get to ...

Answer 2

from 3 to 7 is 4 units up
go another 4 and get to ?

Answer 3

@Ahsome nice picture but i think you misread the question

Answer 4

Whoops ;)

Answer 5

I am honestly so confuzzled right now.

Answer 6

Simply use the MidPoint Formula:

Answer 7

\[\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\]

Answer 8

I am no longer confuzzled! thanks a ton!

Answer 9

Where \((x_1,y_1)\) is the co-ordinate of one end point (R) and \((x_2,y_2)\) is the co-ordinate of another end point (S)

Now, lets do this step by step. The section, \[\left(\frac{x_1+x_2}{2}\right)\]
Tells you the \(x\) value of the midpoint. Since we know x value of the midpoint is 6, we can say that:
\[\left(\frac{x_1+x_2}{2}\right)=6\]
Now, we know that one of the x value for one end was 4 (R Point). So lets put that also
\[\left(\frac{4+x_2}{2}\right)=6\]
Now, \(x_2\) is meant to be the x value for the second end point (S), but since we do not know it, we will simply leave it as \(x\).
\[\left(\frac{4+x}{2}\right)=6\]
Now, if we find the value of \(x\), we will know the \(x\) value for S. So solve away!
\[\left(\frac{4+x}{2}\right)=6\]\[\frac{4+x}{2}=6\]\[4+x=12\]\[x=8\]
Therefore, the \(x\) value for S is \(8\). Do the same thing, but for \(y\) instead it, to get the \(y\) value for S. Here is the equation:
\[\left(\frac{y_1+y_2}{2}\right)=7\]

Answer 10

@Oreolover4876, that should be the steps. If you think I helped, please consider pressing the best response button Thank you :)