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Mathematics 8 Online
OpenStudy (anonymous):

MEDAL AND FAN IF YOU GET IT RIGHT!!!!!!!!!!! SOLVE FOR N http://static.k12.com/bank_packages/files/media/mathml_ca19a8c259aadf1f924f7d4f7efbcef04b018932_1.gif

OpenStudy (danjs):

ohh k

OpenStudy (danjs):

\[(\frac{ 35 }{ 4 } + \frac{ 37 }{ 5 }) + \frac{ 33 }{ 5 } = n + 14\]

OpenStudy (danjs):

multiply everything by a common denominator, 20

OpenStudy (anonymous):

Yep

OpenStudy (danjs):

175+148+132 = 20N + 280

OpenStudy (anonymous):

ok

OpenStudy (danjs):

455 = 20N + 280

OpenStudy (danjs):

20N = 175 N = 175/20

OpenStudy (danjs):

good?

OpenStudy (danjs):

reduce to n = 35 / 4

OpenStudy (mertsj):

\[8\frac{3}{4}+7\frac{2}{5}+6\frac{3}{5}=n+14\] \[8\frac{3}{4}+(7\frac{2}{5}+6\frac{3}{5})=n+14\] \[8\frac{3}{4}=14=n+14\] \[8\frac{3}{4}=n\]

OpenStudy (anonymous):

Can you help with more @Mertsj

OpenStudy (mertsj):

Typo: Should be 8 3/4+14=n+14

OpenStudy (mertsj):

One more if you hurry up

OpenStudy (mertsj):

\[5\frac{2}{3}- \frac{9}{4}\times \frac{5}{3}\] \[5\frac{2}{3}- \frac{15}{4}\] \[ \frac{17}{3}-\frac{15}{4}\] \[\frac{68}{12}-\frac{45}{12}=\frac{23}{12}=1\frac{11}{12}\]

OpenStudy (anonymous):

thanks!

OpenStudy (mertsj):

yw

OpenStudy (mertsj):

Change it to an improper fraction and invert it. That will be the reciprocal.

OpenStudy (anonymous):

ok wasn't sure

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