Solving x^2+8x+6 by factoring?
can not be done
good luck with that program you are going to need the quadratic formula or what is easier in this case is completing the square
Okay, then, how would I go about completing the square in this one?
\[x^2+8x+6=0\] subtract \(6\) \[x^2+8x=-6\] then half of 8 is 4 so \[(x+3)^2=-6+16\\ (x+3)^2=10\]
damn typo \[(x+4)^2=10\] is what i meant, ignore the 3
that makes \[x=-4\pm\sqrt{10}\]
Okay, no, I didn't understand that at all. But I don't know if that would have helped my objective anyway. I need to find the x and y intercepts.
I'd love to just plug it into my calculator, but I have to do it algebraically.
finding the x intercetps is the same as solving \[x^2+6x+8=0\] the \(y\) intercept is\((0,8)\) because if \(x=0\) then \(y=8\)
Yeahh, but what are the x intercepts and how do I figure those out?
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