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Mathematics 21 Online
OpenStudy (anonymous):

please help Suppose a laboratory has a 57 g sample of polonium-210. The half-life of polonium-210 is about 138 days. a. How many half-lives of polonium-210 occur in 276 days? b. How much polonium is in the sample 276 days later? 2; 3,933 g 2; 14.25 g 2; 28.5 g 3; 7.13 g

OpenStudy (danjs):

2

OpenStudy (anonymous):

got that but how do u figure out the rest

OpenStudy (danjs):

half of a half of the original amount

OpenStudy (danjs):

2 half lives means you cut it in half, then half again.

OpenStudy (danjs):

\[57 * \frac{ 1 }{ 2 } * \frac{ 1 }{ 2 }\]

OpenStudy (danjs):

The half life is 138 days, so in 276 days, 2 half lifes will occur, and the sample will be 1/4 th the original size.

OpenStudy (danjs):

or 14.25 g

OpenStudy (anonymous):

b would be my answer

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