If the domain of the square root function f(x) is x<=7, which statement must be true?
7 is subtracted from the x-term inside the radical.
The radical is multiplied by a negative number.
7 is added to the radical term.
The x-term inside the radical has a negative coefficient.
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OpenStudy (anonymous):
s = ut + ½ at2
OpenStudy (anonymous):
s = ut + 1/2 at2
OpenStudy (anonymous):
do you understand that domain in a different form...
OpenStudy (anonymous):
no, sorry.
OpenStudy (anonymous):
@CavebusterWatcher!
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OpenStudy (anonymous):
Are you sure it is not x>=7 because none of those answers work.
OpenStudy (anonymous):
Yeah, I'm sure. See for yourself.
jimthompson5910 (jim_thompson5910):
you could do this trick
x <= 7
x-7<=7-7
x-7 <= 0
-1*(x-7) >= -1*0 ... notice the sign flip
-x + 7 >= 0
7 - x >= 0
-----------------------------------
or you can do it this way
x <= 7
x-x <= 7-x
0 <= 7-x
7-x >= 0
jimthompson5910 (jim_thompson5910):
either way, you go from x <= 7 to 7-x >= 0
OpenStudy (anonymous):
Is it the last option?
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