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Trigonometry 19 Online
OpenStudy (gabyramirezzz):

Let the function f(x) have the form f(x) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of A be? (graph to be added) a) 2 b) 3 c) 4 d) 1

OpenStudy (gabyramirezzz):

jimthompson5910 (jim_thompson5910):

what is the midline in this case?

OpenStudy (gabyramirezzz):

i really have no idea

jimthompson5910 (jim_thompson5910):

alright, how about the highest and lowest points

jimthompson5910 (jim_thompson5910):

the y values (I don't care about the x values)

OpenStudy (gabyramirezzz):

4

jimthompson5910 (jim_thompson5910):

y = 4 and what else

jimthompson5910 (jim_thompson5910):

y = 4 corresponds to the max

OpenStudy (gabyramirezzz):

-4

jimthompson5910 (jim_thompson5910):

y = -4 is the min, yes

jimthompson5910 (jim_thompson5910):

now find the distance from the max y = 4 to the min y = -4

OpenStudy (gabyramirezzz):

8?

jimthompson5910 (jim_thompson5910):

good, then we finally cut that in half to get the amplitude

jimthompson5910 (jim_thompson5910):

so the amplitude is 4 ------------------------------------------------------- the alternative way is to find the midline add up the max and min and then divide by 2 (4 + (-4))/2 = (4-4)/2 = 0/2 = 0 the midline is y = 0 then find the distance from the midline to the max, that is 4 units (same as the distance from the midline to the min). So this is another way to get the amplitude to be 4.

OpenStudy (gabyramirezzz):

oh so its 4? thats it??

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

either way, you're going to get 4

OpenStudy (gabyramirezzz):

thank you so much, can you help me on one more?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (gabyramirezzz):

for the function y= -2+5 sin (pi/12(x-2)) what is the minimum value?

jimthompson5910 (jim_thompson5910):

what is the range of sin(x) ?

OpenStudy (gabyramirezzz):

all real numbers between -1 and 1?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

so if you multiply EVERY output possible that comes out of sin(x) and you multiply the outputs by 5, what is the new range?

jimthompson5910 (jim_thompson5910):

In other words \[\Large -1 \le \sin(x) \le 1\] \[\Large a \le 5\sin(x) \le b\] what goes in place of 'a' and 'b' ?

OpenStudy (gabyramirezzz):

pi and 12?

jimthompson5910 (jim_thompson5910):

you agree that \[\Large -1 \le \sin(x) \le 1\] right?

OpenStudy (gabyramirezzz):

right

jimthompson5910 (jim_thompson5910):

we can multiply every part of that inequality by 5 \[\Large -1 \le \sin(x) \le 1\] \[\Large 5*(-1) \le 5\sin(x) \le 5*1\] \[\Large -5 \le 5\sin(x) \le 5\]

jimthompson5910 (jim_thompson5910):

so 5sin(x) is in between -5 and 5

jimthompson5910 (jim_thompson5910):

with me so far?

OpenStudy (gabyramirezzz):

actually yeah

jimthompson5910 (jim_thompson5910):

so the smallest that 5*sin(x) can get is -5 this is true no matter what x is, so you can replace x with any crazy complicated expression you want and -5 will still be the min

jimthompson5910 (jim_thompson5910):

however

jimthompson5910 (jim_thompson5910):

we have a -2 hanging out front

jimthompson5910 (jim_thompson5910):

so -2+5sin(x) will have a min of -2+(-5) = -7 and again, you can replace x with whatever you want and that min won't change

jimthompson5910 (jim_thompson5910):

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