Let the function f(x) have the form f(x) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of A be?
(graph to be added)
a) 2
b) 3
c) 4
d) 1
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OpenStudy (gabyramirezzz):
jimthompson5910 (jim_thompson5910):
what is the midline in this case?
OpenStudy (gabyramirezzz):
i really have no idea
jimthompson5910 (jim_thompson5910):
alright, how about the highest and lowest points
jimthompson5910 (jim_thompson5910):
the y values (I don't care about the x values)
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OpenStudy (gabyramirezzz):
4
jimthompson5910 (jim_thompson5910):
y = 4 and what else
jimthompson5910 (jim_thompson5910):
y = 4 corresponds to the max
OpenStudy (gabyramirezzz):
-4
jimthompson5910 (jim_thompson5910):
y = -4 is the min, yes
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jimthompson5910 (jim_thompson5910):
now find the distance from the max y = 4 to the min y = -4
OpenStudy (gabyramirezzz):
8?
jimthompson5910 (jim_thompson5910):
good, then we finally cut that in half to get the amplitude
jimthompson5910 (jim_thompson5910):
so the amplitude is 4
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the alternative way is to find the midline
add up the max and min and then divide by 2
(4 + (-4))/2 = (4-4)/2 = 0/2 = 0
the midline is y = 0
then find the distance from the midline to the max, that is 4 units (same as the distance from the midline to the min). So this is another way to get the amplitude to be 4.
OpenStudy (gabyramirezzz):
oh so its 4? thats it??
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jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
either way, you're going to get 4
OpenStudy (gabyramirezzz):
thank you so much, can you help me on one more?
jimthompson5910 (jim_thompson5910):
sure
OpenStudy (gabyramirezzz):
for the function y= -2+5 sin (pi/12(x-2)) what is the minimum value?
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jimthompson5910 (jim_thompson5910):
what is the range of sin(x) ?
OpenStudy (gabyramirezzz):
all real numbers between -1 and 1?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so if you multiply EVERY output possible that comes out of sin(x)
and you multiply the outputs by 5, what is the new range?
jimthompson5910 (jim_thompson5910):
In other words
\[\Large -1 \le \sin(x) \le 1\]
\[\Large a \le 5\sin(x) \le b\]
what goes in place of 'a' and 'b' ?
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OpenStudy (gabyramirezzz):
pi and 12?
jimthompson5910 (jim_thompson5910):
you agree that \[\Large -1 \le \sin(x) \le 1\] right?
OpenStudy (gabyramirezzz):
right
jimthompson5910 (jim_thompson5910):
we can multiply every part of that inequality by 5
\[\Large -1 \le \sin(x) \le 1\]
\[\Large 5*(-1) \le 5\sin(x) \le 5*1\]
\[\Large -5 \le 5\sin(x) \le 5\]
jimthompson5910 (jim_thompson5910):
so 5sin(x) is in between -5 and 5
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jimthompson5910 (jim_thompson5910):
with me so far?
OpenStudy (gabyramirezzz):
actually yeah
jimthompson5910 (jim_thompson5910):
so the smallest that 5*sin(x) can get is -5
this is true no matter what x is, so you can replace x with any crazy complicated expression you want and -5 will still be the min
jimthompson5910 (jim_thompson5910):
however
jimthompson5910 (jim_thompson5910):
we have a -2 hanging out front
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jimthompson5910 (jim_thompson5910):
so -2+5sin(x) will have a min of -2+(-5) = -7
and again, you can replace x with whatever you want and that min won't change