x^3+1 ? real and imagi. zeros
try x=-1 what d you get?
\[ (a+bi)^3 = -1 \]
To better understand, think of it as: \[ (a+bi)^3 = -1+0i \]
isn't the answer umm real=3 or 1 and for imagi= x=+-1?
3^3+1 = 27+1=28 1^1+1 = 1+1 = 2
Do you know complex analysis, or how to convert a number to polar form?
-1 is a solution but it is not imaginary 1 is not a solution and is not imaginary (has no imaginary part...)
y'all are thinking hard about this question
I'm not even thinking about it. I already know the answer.
The real challenge is getting you to understand.
nvm i got it already y'alls answer is way off sorry but my teacher just helped me out
I never gave you an answer.
We didn't give you an answer. We we're proposing ways to solve this.
lol ur formula confuses me
I think that maybe you should go read some of the material leading up to this question. The fact that you said 3, was a solution of this, and that +-1 is an imaginary number, lets me know that you do not have the base material needed to complete this question.
no insulting you, I cant do my homework either lol:)
not*
The only way I can think to solve this without knowing much about complex numbers is to discover that \(-1\) is a root, to then divided by \(x-(-1)\), to get a quadratic expression, and use the quadratic formula to get the remaining roots.
i just did it already lol. thanks tho' and i messed up i looked at the wrong answer instead the real answer is real=3,1 and for imagi= 2, 1
non of those numbers are solutions to the equation and the imaginary numbers you listed are not imaginary
it's actually right tho' and plus my teacher was the one who helped me like few minutes ago and he said that that's the answer
imagi 2,0 *
ok
good luck
thanks ^^ i have a finals tom and i hope i can pass it
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