Question

1.cot x sec^4 x = cot x + 2 tan x + tan^3 x

Answer 1

The cots cancel

Answer 2

sec^4 x = 2 tan x + tan^3 x

Answer 3

tan x = sin x / cos x

Answer 4

So \[(\frac{ 1 }{ \cos x})^4 = 2 \frac{ \sin x }{ \cos x } + (\frac{ \sin x }{ \cos x })^3\]

Answer 5

?

Answer 6

Not sure where to go from here

Answer 7

What are we supposed to do? prove?
One more thing: cannot cancel out cot on that way because from the left hand side it is *, and from the right hand side it is +