Parabola Question

Question

Parabola Question

anonymous · Answer

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anonymous · Answer

Okay, so do you know what to do first?

anonymous · Answer

No~ However if you walk me though it I'm willing to do the math. (:

I have several problems like this so handing me the answer is pointless.

anonymous · Answer

I don't intend to do that, I know how badly that will mess you up.

anonymous · Answer

So, first, we're going to make it so that it's in a y= format not a y^2= does that make sense to you?

anonymous · Answer

Okay! 
The only idea I have would be to take the square root of it- but that doesn't sound right.

anonymous · Answer

That is what you do. And I know it doesn't sound right, but we must have it down to a y=, this will end up having the square root of the rest, but if you look at the answers it makes sense.

anonymous · Answer

When you graph a square root of an x, it will only open up to one side: left or right, so when looking at the answers, you know you can't have it looking like a basic parabola, does that make sense?

anonymous · Answer

$$y=\sqrt{-2/7x}$$
So/that/ is okay to continue?

anonymous · Answer

Yes, because it will open up either left or right now which matches the answers and it's in y= format. That is perfect to continue.

anonymous · Answer

So.. would it open up to the right? 
I'm probably mixing them up so - open up to quadrant 2?

anonymous · Answer

It opens to the left, actually

anonymous · Answer

So quadrant 2, yes.

anonymous · Answer

Aha! I knew I would mix em up.

anonymous · Answer

What's the next step? As it still has a root over it.

(I really appreciate you walking me though this..!)

anonymous · Answer

Before we go to the next step, we should look at our answers and see which ones it can or cannot be.

anonymous · Answer

The second or third answer can't be it, as they open the wrong way.

anonymous · Answer

Yes, and now, if we look at the points, do you think that x or y is going to be zero. Think about a parabola and how it generally works.

anonymous · Answer

I'm not too sure. How exactly can I tell? It would honestly be a 50/50 guess.

anonymous · Answer

Because the graph is a half graph, it will not cross the x-axis in the opposite direction, the grab is opening to the left |dw:1418829528078:dw| and will not go over it.