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Mathematics 10 Online
OpenStudy (anonymous):

A system of linear inequalities is shown below: x + 2y < -5 x - y > 0 Describe the steps to graph the solution set to the system of inequalities.

OpenStudy (shadeyghost):

first, you would get the y by itself by moving the x's to the other side of the equation like so 2y < -x - 5 -y > -x + 0(you don't need this zero anymore)

OpenStudy (anonymous):

I understand 2y < -x - 5, but how did you get -y > -x + 0?

OpenStudy (shadeyghost):

i moved the x to the other side of both equations

OpenStudy (anonymous):

Wouldn't it be y < -x/2 - 5/2

OpenStudy (shadeyghost):

well, yes, but i didnt get there yet, and that isn't completely true

OpenStudy (shadeyghost):

im stupid nvm

OpenStudy (anonymous):

Lol alright, sorry, I'm trying to get some work done, yet I dont completely understand it. @.@

OpenStudy (shadeyghost):

the other one would be y > x, because the - cancels out the other -

OpenStudy (shadeyghost):

and you are done, you just graph them now

OpenStudy (anonymous):

Do I now do the second inequality?

OpenStudy (anonymous):

Nevermind

OpenStudy (anonymous):

How would I graph x - y > 0?

OpenStudy (shadeyghost):

you move the x over to make it -y > -x (+0)

OpenStudy (shadeyghost):

you don't need the zero anymore

OpenStudy (anonymous):

So -y > -x?

OpenStudy (shadeyghost):

yup

OpenStudy (shadeyghost):

then you divide the negative out of the y

OpenStudy (anonymous):

Uhh wait, wouldn't it be x > y?

OpenStudy (shadeyghost):

there you go

OpenStudy (shadeyghost):

wait im confused now

OpenStudy (anonymous):

Oh right because the sign switches.

OpenStudy (shadeyghost):

you are right, so flip the sign on the other one too

OpenStudy (anonymous):

So y < x?

OpenStudy (shadeyghost):

yes

OpenStudy (anonymous):

Thank you

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