Question

What is the range of the function shown below? f(x)=-12/x^2+6

Answer 1

you know that \(\large\color{black}{ x^2 }\) is at least a zero, therefore \(\large\color{black}{ x^2+6 }\) will always be 6 or greater.

This means there is no domain restriction.
the range however will be limited to some small values.

when \(\large\color{black}{ x }\) is 0, then you get \(\large\color{black}{ 2 }\) for the range, you won't get more.
it can't be negative either, although for very high positive values, the function (the output) will approach zero closer and closer.

Answer 2

I mean you get -2 for the range when x=0. sorry.

Answer 3

A. All real numbers
B. All real numbers less than 0
C. All real numbers greater than or equal to -2 and less than 0
D. All real numbers greater than or equal to -2

Answer 4

also, for the NEGATIVE high values, the f(x) will also approach zero.

Answer 5

so c?

Answer 6

@SolomonZelman

Answer 7

yes C is right