...Question in Attachment...

Question

chosenmatt · Answer

76 you getting there

kamibug · Answer

attachment

alexandervonhumboldt2 · Answer

logb  x=y
b^y=x  i guess

lyrae · Answer

$$a^{bx} = c \rightarrow bx = \frac{ \log(c) }{ \log(a) }$$

solomonzelman · Answer

Sorry for a late reply, but what is being applied here is not a change in base formula.
Nor is it an exponential relationship: $\Large\color{black}{ \color{red}{a}^\color{blue}{c}=\color{green}{b}~~~\Rightarrow ~\log_\color{red}{a}\color{green}{b}=\color{blue}{c}       }$

you are simply hitting both sides with a log.

solomonzelman · Answer

disconnected again, love OS, anyways,...

$\large\color{black}{    6^{3x} =18         }$

take the log of both sides

$\large\color{black}{  \log(   6^{3x} )=\log(18)          }$

Then there is a rule: $\large\color{red}{  \log(   a^{b} )=a~\log(b)          }$

applying this to the left side, we get:

$\large\color{black}{ 3x~ \log(   6 )=\log(18)          }$

solomonzelman · Answer

I mean the rule should be:

$\large\color{red}{  \log(   a^{b} )=b~\log(a)          }$

solomonzelman · Answer

(the exponent goes on the outside of the log)

solomonzelman · Answer

if you have any questions, ask:)

kamibug · Answer

I was so confused b/c I had thought it was the exponential relationship and I totally forgot about the rule log(a^b) = b log(a) I couldn't find it in my notes! Thanks again! :)