What is the slope of 3x + 2y = 12?
I write your equation as below: \[y=-\frac{ 3 }{ 2 }x+6\] which is equivalent to your equation so your slope is -3/2
Thank you! Can you help me with some more?
yes! sure!
-3/2 in standart form divide coefficent with x by the coefficent with y and palce an opposite sing from song with oeefiicent of y
ax+by=c sloe is -a/b
If (x, 4) and (2, -1) are 2 points on a line and the slope is ½ , what is the value of x?
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THe slope is 1/2
by definition, slope is: \[\frac{ -1-4 }{ 2-x }=\frac{ 1 }{ 2 }\]
solving that equation, we have: -6=2-x then x=8 is it right?
sorry, I've made an error: -10=2-x so: x=12
is it right?
It's on an extra credit assignment so I don't know
as you answer the questions it spells out a word
What would be the slope of any line perpendicular to 3x + 2y = 10?
Can you do that one?
I think x=12, is right, because I got it using another method.
Twelve is on here as an answer to one of these so it probably is right
the slope of your equation, is: divide by 2 both sides of your equation, namely: \[\frac{ 3 }{ 2 }x+y=5\] then: \[y=-\frac{ 3 }{ 2 }x+5\] so: your slope =-3/2
If a line has a slope of 2 and passes through (4, -1), what is the y-int?
I apply this formula: \[y-y _{1}=m(x-x _{1})\] where: (x_1,y_1)=(4,-1) so: \[y-(-1)=m(x-4)=mx-4m\] then: \[y+1=mx-4m\] finally: \[y=2*x-4*2-1\] \[y=2x-9\]
so if x=0, then y=9
sorry, if x=0, then y=-9
What is the slope of y = 3?
y=3 is this line: |dw:1418854966827:dw| your line is an horizontal line, so slope =0
If the slope of a line is -5 and it passes through (-2, 0), what is the y-int?
I write the equation of your line:
\[y-0=m(x-(-2))=m(x+2)=(-5)*(x+2)=-5x-10\] so: \[y=-5x-10\] and if x=0, then y=-10
What is the slope of the line that passes through (-1, 3) and (5, 0)?
I'm terrible at math, sorry for all these questions I just can't do it
by definition, slope is: \[slope=\frac{ y _{2} -y _{1}}{ x _{2}-x _{1} }\] where (x_1,y_1) and (x_2,y_2) are your points. SO, after substituting, we have: \[slope=\frac{ 0-3 }{ 5-(-1) }=\frac{ -3 }{ 6 }=-\frac{ 1 }{ 2 }\]
oops ...So..., and not SO...
What is the y – int? y – 4 = 1/2 (x + 4)
y-4=1/2 (x+4)
we have to write your equation in the form: y=mx+n so: \[y-4=\frac{ x }{ 2 }+2\] then: \[y=\frac{ x }{ 2 }+6\] finally, if x=0, then y=6
E What is the x-int of -1/2 x - 7y = -14?
if we set y=0, then we have: \[-\frac{ 1 }{ 2 }x-7*0=-14\] \[-\frac{ 1 }{ 2 }x=-14\] multilying both sides by (-2): \[(-2)*-\frac{ 1 }{ 2 }x=-14*(-2)\] finally: \[x=28\]
What would be the slope of any line parallel to y + 3 = -2(x – 1)?
(x-1)
I rewrite your equation as below: y+3=-2x+2 y=-2x+2-3 y=-2x-1 so you initial line has a slope =-2. Now, please, you have to keep in mindthat parallel lines have the same slope, so all parallel lines, to your initial line have to have the slope=-2
please, note taht a slope can not contain the independent variable, namely x
Thank you! I don't have much more I promise
Put y + 2 = 3(x – 4) in standard form. What is the constant term?
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