m^(-5) = 1/32 Help please! Will fan and medal! @sangya21
\[m^{-5}=\frac{1}{m^5} \\ \frac{1}{m^5}=\frac{1}{32} \\ m^5=32 \] can you solve for m now?
maybe. the only next step that pops in my head is 5(square root of) 32.... i suck at math.
ok well you could just raise both sides to the 1/5th power
hint: to get rid of a power you take the square root of that power.
oh and i think that is what you meant
\[(32)^\frac{1}{5}\] i wouldn't call it 5(square root of) 32 though :p
just the 5th root of 32 or 32 to the 1/5th
32 can actually be written as 2^some power
@ frekles what you put is not what i meant omf doubleG Poland gone Tomboy thank you!!!!!!!!!!!!!!!!!!
* @freckles
lol i'm not familiar with that slang \[m^5=32 \\ (m^5)^\frac{1}{5}=(32)^\frac{1}{5} \\ m^{5 \cdot \frac{1}{5}}=(32)^\frac{1}{5} \\ m^1=(32)^\frac{1}{5} \\ m=(32)^\frac{1}{5}\]
now (32)^(1/5) can be simplified further
you know 32 is even so 2 is a factor of 32 32=2(16) 2 is also a factor of 16 since 16 is even 32=2(2)(8) blah blah blah 32=2(2)(2)(2)(2)
how many factors of 2 are in 32?
i already have the answer. thx anyhow!!!
np
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