Honors Algebra 2, continued.

(sorry about that, computer is acting up)

Question

Honors Algebra 2, continued.



(sorry about that, computer is acting up)

haleyelizabeth2017 · Answer

Divide and simplify if possible.
$\frac{ \sqrt {250x^{16}} }{ \sqrt {2x} }$

anonymous · Answer

sorry im new to this and that equation tool isn't working for me. but you can split the numerator into sqrt(125 x^8) * sqrt(2x) * sqrt(x^7)

haleyelizabeth2017 · Answer

okay....

haleyelizabeth2017 · Answer

$$\frac{ \sqrt {125x^8} \sqrt {2x} \sqrt {x^7} }{ \sqrt {2x} }$$

anonymous · Answer

Yes, and then cancel the sqrt(2x) from the numerator & denominator; so you'd end up with sqrt(125x^8) * sqrt(x^7). 

You can multiply what's inside the square roots to get (sqrt(125x^15)) and then simplify that to = (x^7)(sqrt(125x))

anonymous · Answer

Sorry, it looks really messy typed out..

haleyelizabeth2017 · Answer

okay......haha

anonymous · Answer

haha hope it was all understandable :)

haleyelizabeth2017 · Answer

so $$\sqrt {125x^8} \sqrt {x^7}$$
$\sqrt {125x^{15}}$

$x^7 \sqrt {125x}$

anonymous · Answer

Yes :)

haleyelizabeth2017 · Answer

okay thank you!

anonymous · Answer

you're welcome

haleyelizabeth2017 · Answer

@EricWise here is the other method :)

haleyelizabeth2017 · Answer

jacquelyn made it easy to understand :) easier at least