Question

Which substance is the reducing agent -> Cr + MnO4^- + 2H2O = MnO2 + Cr(OH)3 + OH^-

Answer 1

in order to do this properly, you need to assign oxidation states to all the atoms

\( Cr + MnO_4^- + 2~H_2O \rightarrow MnO_2 + Cr(OH)_3 + OH^-\)

the important atoms here are Mn and Cr

Answer 2

So Mn is the oxidizing agent and Cr is the reducing agent?

Answer 3

indeed

Answer 4

Thank you