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write an explicit formula for the sequence 7,2,-3,-8,-13,... Then find a^14
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note that, your sequence is an arithmetic progression, whose first term is 7, and constant c=-5, so generic term a_n, is given by the subsequent formula: \[a _{n}=a _{1}+(n-1)*c=7+(n-1)*(-5)=\] \[=7-5n+5=12-5n\] so, please, substitute n=14, and you will get your answer
ok i got 98
no, sorry: \[a _{14}=12-5*14=...\]
\[a _{14}=-58\] @bandnerd24
oh well thanks for the help
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thanks!
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