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Simplify. Write in radical form.
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Haley hey :D
\[\Large\left( \frac{ x^3y^{-2} }{ xy } \right)^{-\frac{ 1 }{ 5 }}\]
-5 root this whole thing
I know I need to do that, I'm just confused on what I would get.....
Give me one second
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well first off the x^3 y^-2 / xy
How would x and y effect the x and y on the top?
some cancel
\(\Large\left( \frac{ x^2y^{-2} }{ y } \right)^{-\frac{ 1 }{ 5 }}\)
I'm not sure about the y...
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the y would make it y^-3 on the top
okay....
Go ahead and rationalize the denominator.
so \((x^2y^{-3})^{-1/5}\)?
I mean put y into the denominator
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I'm confused
( x^2 / y^3 ) ^ -(1/5)
right now
\[\Large\left( \frac{ x^2 }{ y^3 } \right)^{-\frac{ 1 }{ 5 }}\] So this?
Yup
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|dw:1418862971738:dw| so that's how he got y^(-3)
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