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Mathematics 13 Online
OpenStudy (anonymous):

which of the following is a one-to-one function

OpenStudy (zzr0ck3r):

the functions?

OpenStudy (zzr0ck3r):

a function \(f\) is said to be one-to-one provided that if \(f(x)=f(y)\) then \(x=y\)

OpenStudy (anonymous):

OpenStudy (misty1212):

the two lines are one to one, the rest are not one to one i think

OpenStudy (zzr0ck3r):

be careful on the first one \(f(0) = f(1) = 2\)

OpenStudy (zzr0ck3r):

for the third one [[2(1/3)]]=[[2(1/3.5)]] for the 4th (-1)^2=1^2

OpenStudy (anonymous):

I got D?

OpenStudy (zzr0ck3r):

why?

OpenStudy (zzr0ck3r):

(-1)^2=1^2=1 can you see why this shows it is NOT one to one?

OpenStudy (zzr0ck3r):

because we have f(1) = f(-1) but 1\(\ne\)-1

OpenStudy (anonymous):

B

OpenStudy (zzr0ck3r):

why?

OpenStudy (zzr0ck3r):

you are right, I just hope that was not a lucky guess:P i.e. I hope you understand why.

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