Solve for x. -ax + 2b > 8 http://i.imgur.com/FLuD7Cl.png
first subtract 2b from both sides and what do you have?
-ax > 8 - 2b
-ax > -2b + 8 I mean.
well actually we have a problem
without knowing if a is negative of positive or 0 we cant go any further without cases
So its B.
Since dividing both sides by -a.
I am saying that the question is a bad question and you should tell your teacher that you cant solve it without knowing if a is negative, positive, or 0
a is negative.
you say that because you see a - sign right?
Mhm.
well what is -(-3)?
But its not like that.
so if a=-3 -a = 3 > 0
ok let us assume -a is negative number
Plus all of them have -a, except D which is wrong since it has -2b - 8
nope
because notice they remove the negative from the bottom, that will change the top
ok lets assume its negative then you have -ax> 8-2b right?
Yes
now we divide by -a and since we are assuming its negative, we flip the sign \(x< \frac{8-2b}{-a}\) you with me?
oh ok, then yes its c, I thought it has an a on the bottom
err b
It is C?
Oh
But you should tell your teacher that this is a bad question. They will be happy if you understand why. notice that they did not tell you anything about a, so a could be any real number what if we choose a=-3 -(-3)x+2b>8 we subtract the 2b -(-3)x>8-2b this is the same as 3x>8-2b now we divide by 3 and the sign never gets flipped
so depending on the sign of a we get different answers also, a could be equal to 0 so we have -0x+2b>8 2b>8 now we cant even solve for x this problem is bad on many levels and you should complain if you are paying for the class.
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