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Mathematics 8 Online
OpenStudy (anonymous):

WILL FAN AND MEDAL

OpenStudy (anonymous):

OpenStudy (danjs):

For the last one, add up all the fractions, x^a*x^b = x^(a+b)

OpenStudy (danjs):

the fourth root of x is the same as x^(1/4)

OpenStudy (danjs):

The last one you get x ^(16/4) = x^4

OpenStudy (anonymous):

wait so this is al for Toms equation?

OpenStudy (anonymous):

*all

OpenStudy (danjs):

Yeah tom, adds up to x^(16/4) or x^4

OpenStudy (anonymous):

ohh ok thank you. do you know the other ones?

OpenStudy (danjs):

Lets see,

OpenStudy (danjs):

Tom \[(\sqrt[3]{x})^{12} = x ^{\frac{ 12 }{ 3 }} = x ^{4}\]

OpenStudy (danjs):

That was Kevin, sorry

OpenStudy (anonymous):

lol it's ok

OpenStudy (danjs):

Deb \[\sqrt[4]{x^3 + x^5 + x^8 } = x ^{\frac{ 3 }{ 4 }} + x ^{\frac{ 5 }{ 4 }} + x ^{\frac{ 8 }{ 4 }}\]

OpenStudy (danjs):

3/4 + 5/4 + 8/4 = 16/4 \[x ^{\frac{ 16 }{ 4 }} = x ^{4}\]

OpenStudy (danjs):

Deb is good too

OpenStudy (danjs):

Joe is no good

OpenStudy (anonymous):

oh so Deb is the correct one, alright

OpenStudy (danjs):

no, Deb, Kevin, and Tom are all correct

OpenStudy (anonymous):

how do i do joe's? @DanJS

OpenStudy (danjs):

For joe...

OpenStudy (anonymous):

oh wait sorry you already did it lol

OpenStudy (danjs):

no i didnt do joes yet

OpenStudy (danjs):

\[[x ^{5/4} * x ^{7/4} ] * x ^{-1/4}\]

OpenStudy (danjs):

When you have a exponent in the bottom, you can move it to the top by making it negative

OpenStudy (danjs):

Now distributing these, and adding their exponents gives,... \[x ^{4/4} + x ^{6/4}\] (5/4 - 1/4) = 4/4 (7/4 - 1/4) = 6/4

OpenStudy (anonymous):

ooo i didn't know that

OpenStudy (danjs):

\[x ^{10/4} = x ^{5/2} \neq x^4\]

OpenStudy (danjs):

So joe is incorrect.

OpenStudy (danjs):

any part you dont understand?

OpenStudy (anonymous):

ohhkay. thank you i appreciate it. i already fanned and gave you the medal lol

OpenStudy (anonymous):

i think i understand

OpenStudy (danjs):

here is what you need to remember...

OpenStudy (danjs):

Just using \[x^a * x^b = x ^{a + b}\] \[\sqrt[a]{x} = x ^{1/a}\] \[\frac{ 1 }{ x ^{a} } = x ^{-a}\]

OpenStudy (anonymous):

oh so first i combine the base

OpenStudy (danjs):

The exponents

OpenStudy (anonymous):

where does the b go for the second step?

OpenStudy (danjs):

like the first property, x to a power times x to another power, equals x to the powers added together

OpenStudy (anonymous):

ohh so if im multiplying the base, i add the exponents?

OpenStudy (danjs):

No those are 3 separate properties of exponents.

OpenStudy (danjs):

yeah , the first property is if you have the same base multiplied together with exponents on them, you add the exponents

OpenStudy (danjs):

The second property is, if you have a root, it is the same thing as x raised to the 1/n power, where n is the root

OpenStudy (danjs):

like square root of x is the same as x raised to the 1/2 power cubed root of x is the same as x raised to the 1/3 power

OpenStudy (danjs):

The third property, is if you have a base raised to a power in the denominator, you can move it to the top by making the power negative.

OpenStudy (danjs):

That is all you really have to remember.

OpenStudy (danjs):

The only other one, that was not in this problem is: a power raised to a power \[(x ^{a })^{b} = x ^{a*b}\]

OpenStudy (danjs):

You multiply the powers in that case, not add them

OpenStudy (anonymous):

ohh alright. gotchu

OpenStudy (anonymous):

thank you for helping me understand :) @DanJS

OpenStudy (danjs):

no prob... just practice those 4 rules, and you will be able to do any problem with exponents

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