Calculate the result of the following formula: P(14,7) Don't want the answer, just don't understand how to solve.
\[\rm P(n, r) = \dfrac{n!}{(n-r)!}\]
\[\rm P(14, 7) = \dfrac{14!}{(14-7)!}\]
do you know how to work a factorial ?
We eliminate the the overlapping numbers to reduce the work I think...
14*13*12...*3*2*1
yes!
The number seems awfully large which is throwing me for a loop.
\[\rm P(14, 7) = \dfrac{14!}{(14-7)!}= \dfrac{14!}{7!}\\\]
\[ = \dfrac{14\times 13\times 12\times 11\times 10\times 9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{7\times 6\times 5\times 4\times 3\times 2\times 1}\]
\[\require{cancel} = \dfrac{14\times 13\times 12\times 11\times 10\times 9\times 8\times \cancel{7\times 6\times 5\times 4\times 3\times 2\times 1}}{\cancel{7\times 6\times 5\times 4\times 3\times 2\times 1}^1}\]
Ohhhhhh!!!!!
I KNEW there was some sort of elimination process.
\[=14\times 13\times 12\times 11\times 10\times 9\times 8 \]
:) you still need use your calculator ^
Yea, it's still a giant number.
So I have this oversized number. What's to be done with it now?
you're done, thats the value of P(14, 7)
p(14,7)=121080960
That just seems...excessive.
How'd I goof THAT up...
looks you have multiplied by 7
you should stop at 8
Yep. Spot on. Do you, by chance, know the name of that formula?
P(14,7) = 14x13x12x11x10x9x8
permutation formula
You're top notch. Thanks so much for help! I have a much better grasp on these sort of equations and that formula.
you're welcome :)
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