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Find dy/dx if a) ye^3x=2
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@zepdrix
\[\Large\rm y e^{3x}=2\]This will be very very similar to the last one. Start by dividing both sides by e^(3x),\[\Large\rm y=\frac{2}{e^{3x}}\]Remember your exponent rules? One of them allows us to write the expression like this:\[\Large\rm y=2e^{-3x}\]
Taking a derivative from this point will be similar to the last one. The exponential will give us the same thing back, but we need to apply the chain rule.
\[\Large\rm y'=2e^{-3x}(-3x)'\]
So what do you end up with? :d
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-6e^-3x
Good good good. :)
Thank you @zepdrix
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