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Mathematics 17 Online
OpenStudy (anonymous):

What's the inverse of y=a^x

OpenStudy (jhannybean):

\[\large \color{red}y=a^\color{red}x\]switch x and y.

OpenStudy (jhannybean):

And then tell me what you get.

OpenStudy (anonymous):

then resolve for y

OpenStudy (jhannybean):

Are you able to write your equation once you switch the variable, @minisweet4 ?

OpenStudy (anonymous):

x=a^y then would I have to square root something

OpenStudy (jhannybean):

Not exactly.

OpenStudy (anonymous):

to undo a base to an exponent you log it

OpenStudy (jhannybean):

because we see y is a power, we can use log rules to bring that power down. take the natural log of both sides,

OpenStudy (jhannybean):

And write down what you have once you do that.

OpenStudy (anonymous):

I honestly don't know how to do the next part

OpenStudy (jhannybean):

multiply \(\ln\) to both sides, and write it down :)

OpenStudy (jhannybean):

Then we will move on to the next step.

OpenStudy (zzr0ck3r):

I would not say "multiply" ln(x) is a function..so we need to take ln of both sides, but to know what ln is you must know what \(y=a^b\iff \log_a(y)=b\)

OpenStudy (zzr0ck3r):

its sort of built into the definition...

OpenStudy (tkhunny):

Do NOT "multiply ln". That does not mean anything. "ln" is NOT a factor. It is a function. You have \(y=a^{x}\) Introduce the logarithm: \(ln(y)=ln\left(a^{x}\right)\) -- No multiplication going on, there.

OpenStudy (jhannybean):

She wasn't taking the natural log of both sides, so instead to visualize i said "multiply" eh

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