@Directrix
The problem statement is ?
A funnel has a filter that was being used to remove impurities from a solution, but it became clogged and stopped draining. The remaining solution is represented by the colored region. The top of the solution is 2 cm from the bottom of the funnel and at a point where the diameter of the funnel is 3 cm. Assuming the funnel is cone-shaped, how many cubic centimeters of the solution should remain in the funnel?
Okay, here is what we are working with. It is a cone, too.
Next up, the forumla for the volume of a right circular cone.
if you added to the attachment i cant see it seems like its not big enough i can only see a portion of t
That is correct. The portion you see is the portion of the original cone in which the stopped-up filter has trapped fluid. Our task is to get the volume of that fluid.
V = 1/3 * π * r^2 * h V = 1/3 * π *( 1.5)^2 * 2 V = 4.7 cubic cm Note that the "WolfRam" calculator will do the arithmetic. Click on this link: http://www.wolframalpha.com/input/?i=+1%2F3+*+%CF%80+*%28+1.5%29%5E2+*+2+%3D
4.5?
I got 4.7. Did you use 3.14 for the pi approximation?
Even so, I still get 4.7
i got it now ,alright time to get your medals
Then, start a new thread with the next question. Then, close that thread to get out of the way of traffic.
wait how will i do this exactly
Click on "Open Questions" and post yours.
alright
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