Question

Can someone check my work for me please?

Answer 1

Given the trinomial 2x2 + 4x + 4, predict the type of solutions.

Answer 2

i think thats has 2 complex solutions

Answer 3

@absolutemaster

Answer 4

no, it has 2 real solutions

Answer 5

look at the determinant b^2-4ac= 4^2-4*2*4 = 16-32 = -16<0

so there are two non real solutions

Answer 6

oh, i got a negitive number when i did the discriminant thing

Answer 7

2 complex solutions you are right.....

Answer 8

discriminant*

Answer 9

you are right

Answer 10

if you divide by 2
X^2+2x+2=0
there are no real # if you multpily them will give you 2and if you add them will give 2

Answer 11

Lol how bout another one? ;)

Answer 12

Given the trinomial 3x2 - 6x + 5, what is the value of the discriminant?
i got -24

Answer 13

@zzr0ck3r

Answer 14

6^2-4*3*5 = 36-60 = -24

Answer 15

\(\huge\checkmark\)

Answer 16

Select one of the factors of 5x2 + 7x + 2.

im not sure how to start this really..

Answer 17

5*2 = 10 we want to numbers that multiply to 10 but add to 7

Answer 18

what are those numbers?

Answer 19

we want two numbers ....*

Answer 20

oh 5 and 2.. wow

Answer 21

hehe

Answer 22

took me a second..

Answer 23

wow... that just really confused me.. btw the answers could be
(5x - 2)
(x + 2)
(5x + 1)
None of the above

Answer 24

ok sorry I read something wrong...

Answer 25

take those two numbers and expand the middle term

\(5x^2+7x+2=5x^2+5x+2x+2\)

right?

Answer 26

yes.. so x(5x+5)

Answer 27

or something

Answer 28

we factor what we can out of the first two terms

\(5x^2+5x+2x+2=5x(x+1)+2x+2\)

then we factor what ever we can out of the 3rd and 4th term so that we get the same thing

\(5x^2+5x+2x+2=5x(x+1)+2x+2=5x(x+1)+2(x+1)\)

Then we factor the \((x+1)\) out

\(5x^2+5x+2x+2=5x(x+1)+2x+2=5x(x+1)+2(x+1)=(x+1)(5x+2)\)

Answer 29

\(5x^2+5x+2x+2=5x(x+1)+2x+2=5x(x+1)+2(x+1)=\\(x+1)(5x+2)

\)

Answer 30

good night

Answer 31

thank you.. so the answer is none of the above?