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OpenStudy (anonymous):
OpenStudy (anonymous):
this like the first one;
OpenStudy (anonymous):
you find the point the descriped in the formula
you find in the line or function (x1,-2)
OpenStudy (anonymous):
the points are (1-2) and (2,2)
OpenStudy (anonymous):
justs one (1,-2)
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OpenStudy (anonymous):
in the formula is write y-y1
OpenStudy (michele_laino):
then we can write:
\[2+2=m(2-1)\]
so:
\[m=4\]
OpenStudy (anonymous):
the y1= -2 and x1 =1
OpenStudy (anonymous):
can you explain more?
OpenStudy (anonymous):
o.k the fromula have itself minus
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OpenStudy (anonymous):
if you see that written y- (-2) = m(x-x1);
that the y1 = -2 not to 2
OpenStudy (michele_laino):
because your line has to pass at point (2,2), and equation of your line, is:
\[y+2=m(x-1)\]
so, if I substitute the coordinates of point (2,2) into above equation, I have:
\[2+2=m(2-1)\]
OpenStudy (anonymous):
you choose two point find the slope and the points in formula is (1,-2)
OpenStudy (anonymous):
so would the answer be y-(-2)=4(x-2)
or
y-(-2)=4(x-1)
OpenStudy (anonymous):
second one
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OpenStudy (michele_laino):
no, please:
y-(-2)=4(x-1)
OpenStudy (anonymous):
i do not know which one to give the medal too.. you guys both helped me out the same..
OpenStudy (michele_laino):
ok! I give a medal to @borak , and you give a medal to me, please
OpenStudy (anonymous):
so the answer is y-(-2)=4(x-1)
OpenStudy (anonymous):
the slope as you see 4 , yes the answer is right
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