how do i do this?.... the lengths of the sides of a triangle are in a ratio of 3:6:8. the perimeter of the triangle is 510cm. find the length of the largest side.

Question

amistre64 · Answer

since the ratio stays the same; some multiple of them will produce the desired perimeter

amistre64 · Answer

if our side lengths were a ratio if :  a:b:c

and they added up to some value k

then we could determine that n(a+b+c) = k and solve for n.

the side lengths would therefore be: an, bn, cn

jose_alamo32 · Answer

so a=3 b=6 c=8. so i add them and get k? but how would get n?....can you tell me the answer? im not 100% on it

amistre64 · Answer

k = the perimeter; so we are adding them all up to get the perimeter.

n is the only unknown now.

3n + 6n + 8n = 510

or:  n(3+6+8) = 510, solve for n

we see that 8n is going to be the longest side:

jose_alamo32 · Answer

o ok lol wow thats easy. thank you and have another one..... the measures of two supplementary angles are in the ratio 4:11 what is the measure of the smallest angle? that would be 4 right?

amistre64 · Answer

the smallest angle would be 4n  yes

supplementary angles add up to 180 soo

4n + 11n = 180,  its the same solution concept as the other one

15n = 180, therefore n=180/15

the angle is therefore:  4(180)/15

jose_alamo32 · Answer

alright thank you :)

amistre64 · Answer

good luck :)