Question

A box has a weight of 120 lbs and the bottom of the box is 12 in2
. What is the pressure the box exerts on the
floor?

Answer 1

Pressure is defined as
P=F/A
where F= force and A=area of effect

in this case the only force you can recall would be weight.
Weight is W=m*g
where g=gravitational acceleration, 32.17 ft/s^2
So...
P=m*g/A

You know m=120lbs
A=12 in^2
and g can be considered a constant
So you can solve for Pressure

Answer 2

thanks

Answer 3

You're welcome

Answer 4

ok im lost again , so i divide 12in into120lbs ?

Answer 5

@KamiBug

Answer 6

the area, A=12 in^2
the mass, m=120 lbs
the gravitational constant, g=32 ft/s^2=384 in/s^2
ft=feet
in=inches
s=seconds
lbs=pounds
P=pressure
\[P=\dfrac {m \times g} {A}\]
\[P=\dfrac {120lbs \times 384 ( inches/s^2)} {12 inches^2} \]

Answer 7

Thank You again

Answer 8

by the way, pounds are a mass unit, not a weight unit.

Answer 9

A bronze statue weighs 2400newtons & has a base that is 4 meters 1/2 meters. what is the pressure statue exerts on the floor ?

Answer 10

That's your base, so the area of effect would be the area of that quadrilateral

Now, they give you the Force (Weight) that is 2400 N
N=Newtons
Now, N/m^2 = Pa
Pa= Pascal, a presure unit

We recall the pressure eq
P=F/A
And you know the force, 2400N
You can calculate the area (area of a quadrilateral)
And then you'll obtain the pressure

Answer 11

ughhhh , so how my question going to look when i solve it ?