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Mathematics 16 Online
OpenStudy (anonymous):

Determine the intervals on which the function is increasing, decreasing, and constant.

OpenStudy (anonymous):

OpenStudy (anonymous):

The answers are: increasing x > 0; decreasing x < 0 decreasing on all real numbers increasing on all real numbers increasing x < 0; decreasing x > 0 I think it's increasing on all real numbers. Is that right? Or no? @HelpOfTheGods

OpenStudy (solomonzelman):

oh, you are given the graph... don't even have to find the second derivative...LoL

OpenStudy (solomonzelman):

Increasing = positive slope. (the slope can become smaller too, but as long as it's positive) Decreasing = negative slope. (the slope can be growing towards positive, but as long as the graph is going down, now matter how steeply, that is decreasing.) Concave up= the slope is becoming grater and greater. (The slope can be always negative, but if it is growing, then it is concave up.) Concave down = the slope is becoming smaller and smaller. (The slope can be a positive number but if it is becoming a smaller slope that it ios still concave down.)

OpenStudy (solomonzelman):

On your graph, is there any interval where the slope is negative?

OpenStudy (solomonzelman):

yes, yes, sorry, didn't see your post. yes it is increasing on the entire function.

OpenStudy (solomonzelman):

you are right.

OpenStudy (anonymous):

Okay thank you. I just wanted to make sure it was right! :) I appreciate your help.

OpenStudy (solomonzelman):

(the concavity though is: Down when x>0, and Up when x<0. and inflection point (looks like) (0,0) )

OpenStudy (solomonzelman):

yw

OpenStudy (solomonzelman):

I mean not (0,0) but (0,1)

OpenStudy (solomonzelman):

anyways, have fun with tyour math :)

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