what are the zeros of the function f(x)=(5x^2-25x)/x

Question

elonasushchik · Answer

In order to find the zeros, set the function equal to zero (y = 0). 
The given expression, f(x) = (5x^2 - 25x)/x can be simplified as follows: 
f(x) = x(5x - 25)/x 
then you can cancel the x from the numerator and the denominator which gives: 
f(x) =5x - 25 
Subsequently, set f(x) = 0 
5x - 25 = 0 
5x = 25 
x = 25/5 
x =5 

Hence, the only zero is 5 and not zero. 

I believe that the mistake you were making is not canceling the x's from the numerator and denominator..I assume you did the following: 
(5x^2 - 25x)/x = 0 
5x^2 - 25x = 0 
x (5x - 25) = 0 
x = 0 and 5x - 25 = 0 
5x = 25 
x = 25/5 
x = 5 

which gave you two zeros: x = 0 and x = 5 

So, the answer is just x = 5 

Hope this helps!

elonasushchik · Answer

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anonymous · Answer

thanks @ElonaSushchik idk how to give medal

elonasushchik · Answer

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elonasushchik · Answer

Thanks!