What number should be substituted for the question mark to balance the equation? 2C2H6 +?O2 → 4CO2 + 6H2O + heat A. 3. B.7 C.5 D.4
make sure the total number of O atoms on both sides are equal. I count 4x2 O's in the \(CO_2\) and 6x1 O in the \(H_2O\), so how many O atoms is that total?
i dont know. im spastic and panicking right now, cant think
@JFraser
count the O atoms that are on the right side of the arrow.
there are 14 total
ok, on the left there are 2, without the substitute,right? @JFraser
that cant be right.
almost. the subscript tells you that each oxygen MOLECULE has 2 oxygen ATOMS
it's the total number of ATOMS that has to be the same on both sides.
what the difference between a number in front of the element symbol and behind it? thats the major thing that screwing me up.
@JFraser
the subscript after tells you how many of each atom make up one COPY of that molecule
the coefficient in front tells you how MANY COPIES of each molecule need to be used
still confused. @JFraser
im counting 12 atoms on the left. 2x2 +6 + 2
sorry if im frustrating you....
@Abhisar can you help me?
WHat are you not able to understand?
i know the answer is seven (something i cannot understand how i know) but i have no idea how the number is relevent to the situation
@Abhisar
alright then....
See it's very easy, while balancing you need to make sure that number of each atom is equal on both the left hand and right hand side...
Since, you know that the answer is 7. Let's check why it is so...
i've tried counting atoms on the left and keep getting 12 @Abhisar
Now let's see if we get 14 atoms on left hand side when we put 7 at the place of ?. Is 7x2=14 ? YEs...so we get 14 oxygen atoms by replacing ? with 7. Thus the answer is 7. Getting it?
Let's first check how many oxygen atoms are there on the right hand side of the equation. \(\sf 2C_2H_6 +?O_2=\boxed{4CO_2 + 6H_2O}\) + heat Right hand side is the boxed part of the equation. There are 4X2=8 oxygen atoms from the \(\sf 2CO_2\) part and 6 oxygen from the \(\sf 6H_2O\) part. So total 8+6=14 oxygen atoms on right hand side...
2C2H6 + ?)O2...... i keep thinking 2x2 + 6 + 2 @Abhisar
I think the responses showed up in wrong order due to some reason....But is it clear now?
Counting number of oxygen after replacing ? with 7 Left hand side \(\sf 7O_2\) Number of oxygen = 7X2=14 Right hand side \(\sf 4CO_2\) Number of oxygen= 4X2=8 \(\sf 6H_2O\) Number of oxygen= 6X1=6 Total on RHS=8+6=14
nvm i passed the test @Abhisar
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