Hey, I need help badly!
I which point does the curve and the line intersect?
1, 1?
Yep, and that's your answer. When sloving graphically the solution to any system of equations (linear or nonlinear) are points where the function curves, lines etc. intersect.
are all the points* Nonlinear systems usually have several solutions.
Thank you! :) And this?
Np :) All points in the green shaded area, so you'll have to check if the the points given in the answers options are in that area or not.
And it looks like (1,1) is the only one present there.
So I'm correct! Yupppeee :-)
It's D here, right? @Lyrae
Yup :)
@Lyrae For this I graph each one, rite?
Yes that's one way to do it.
I tried, but too many match.
You can also insert the x and y-values of each point into inequalities and see one of them one (or several) of them are violated.
Ahh! Will do. Plug in, eh?
@Lyrae Aye, you're awesome. What's your name?
Carl
And thx :)
So the answer is B?
It was True for each of the equations when I plugged in for B. (-4, -15)
Thanks again, Carl.
Yup, that's what i got too. Anytime :)
I don't know what to do for this problem @Lyrae
It's a point outside the shaded area, and not any of the red lines.
For the previous one i noticed there are actually another point witch satisfies all the inequalities (-4,-4).
So was it B. (-4, -15) for that one or C. (-4, -4)
The assignment also mentions that you have to select a point on a vertice.
So?
This means that you have to check where a bunch of lines intersect.
y = 3x-5 y = -1/2*x + 2 => x = 2, y = 1 y = -4 y = 3x-5 => x = 1/3, y = -4 y = -4 y = -1/2*x + 2 => x = 12, y = -4 None of the x, y pairs maches a point in the answers. |dw:1418939854308:dw| Not any of the point are one the lines either.
Therefore it can't be any of those two points (B or C). And when looking again you see that (-4, 4) also is a valid point, and it's on the the line (boundary) of the second inequality. x= -4 y = -1/2 x + 2 = -1/2 * -4 + 2 = 4 => x = -4, y = 4
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