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Solve for x. 3^(x-2)=5^x
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\[3^{x-2}=5^x\]
oh wait i think i got it
\[\log_{3}5^x=x-2 \] \[x \log_{3}5=x-2 \] is this right?
we have: \[\left( \frac{ 3 }{ 5 } \right)^{x}=9\] then: \[x \log _{10}(3/5)=2 \log _{10}3\] and: \[x=\frac{ 2 \log _{10}3 }{ \log _{10}(3/5) }\]
yes! it is!
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Awesome, I totally forgot i had to use that rule
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