Can someone please help? Trying to get exempt from the final! I'll fan whoever answers
You have to write the equation in slope-intercept form?
i know that, i don't know how to.
y=mx+b is slope intercept form b= y intercept and in this case b=3 m=slope to find the slope find 2 coordinates and replace them into the formula x1-x2/y1-y2
okay so whats the equation for Slope intercept form?? @_ashleeey
Of course, you WILL have to do two equations and decide which to use when. The one with positive slope lends itself to the Intercept Form. Just write it down. \(\dfrac{x}{1}+\dfrac{y}{-1} = 1\).
mx + b @claritamontano
x and y would be (4,3) right? @tkhunny
okay so what does M stand for?
x?
mx+b=y
thats the equation right. So what you do is you find what the slope is ( m)
isnt it 4?
(4,3) is a very important point. That point must be included in both equations. It is the ONLY point with this property.
So how you do that, you go o a point on the graph that hits a point exactly with two numbers and then do rise over run. until you hit another point.
How did you get 4???
okay, so its (4,3) right now, and i go up two right?
the x value
Obvious points for the positive slope are (0,-1)(1,0)(4,3) Obvious points for the negative slope are (4,3)(7,0)
but m isnt the x value its the slop and to find the slope you do rise over run
did you find all those on the line? @tkhunny and @claritamontano okay but i start on 4,3 then do rise over run from there right?
no, if you start there, you wont get anything cause there is no line that goes up. Start at 9, -2 and do rise over run
i ended up figuring this one out, thank you, can you help with my last two though?
yeah sure! Open a new one tho
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