MEDAL What are the solutions of 3x2 + 4x = -5? the quantity negative 4 plus or minus i square root of 66 all over 6 the quantity negative 2 plus or minus 2i square root of 66 all over 3 the quantity negative 2 plus or minus i square root of 11 all over 3 the quantity negative 4 plus or minus i square root of 11 all over 6
@khusker
@DanJS
Have you studied the quadratic equation in your class?
\[x = \frac{ (-b) +- \sqrt{b^2 - 4 * a * c} }{ 2a }\] where \[ax^2 + bx + c = 0\]
Your equation is: 3x^2 + 4x + 5 = 0, so a = 3 b = 4 c = 5
using those values, in the quadratic formula above ...
i'm confused lol
ohhhhh
\[x = \frac{ -4 +- \sqrt{4^2 - 4*3*5} }{ 2*3 }\]
The square root is going to contain a negative number, meaning imaginary/complex numbers
i got -44
right, recall the square root of -1 is i
\[\sqrt{-44} = \sqrt{-1 * 4 * 11} = \sqrt{-1}\sqrt{4}\sqrt{11} \]
\[2i * \sqrt{11}\]
so would that be -2 square root of 11
2i square root 11
i though i equals -1. or is that i squared
*thought
\[\sqrt{-1} = i\]
so \[i^2 = -1\]
soo i'm guessing it's C?
\[x = \frac{ -4 +- 2i \sqrt{11} }{ 6 } = \frac{ -2 +- i \sqrt{11} }{ 3 }\]
yes!! i was right lol
just divided each term by 2 there to reduce it
ohkayy. thank you so much
so it is the 3rd answer
no prob, anytime
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