Question

The probability of a computer chip failing is 2% . if 100 computers are sold, what is the probability of 2 computer chips failing?

Answer 1

(2%)^2*(98%)^98

Answer 2

what is it as a percent ? @caozeyuan

Answer 3

you can try calculating on your caculator, I'll do that in a sec

Answer 4

i did, but it doesn match up to any of the answers.

Answer 5

the possible answers are 8.1 % , 2.7% and 27.3% and 12.1 %

Answer 6

shoot!

Answer 7

Do you have the key? if you do, check if 27.3% is right

Answer 8

i dont have the key.

Answer 9

The solution is found from the binomial distribution, as follows:
\[\large P(exactly\ 2\ fail)=100C2\times(0.02)^{2}\times(0.98)^{98}=you\ can\ calculate\]

Answer 10

100C2 = 4950. Therefore the required probability is given by:
\[\large 4950\times(0.02)^{2}\times(0.98)^{98}=you\ can\ calculate\]
Note: Multiply the result by 100 to give the answer as a percentage, as required by the answer choices.

Answer 11

I forgot my 100C2 cuz I am done with stats 2 years ago, and yeasterday I am done with College Math completely

Answer 12

27.3% ? @kropot72

Answer 13

Yes, that is correct.

Answer 14

another question you might be able to help with. ::: two marbles are to be pulled from a bag that contains 2 yellow marbles, 4 green marbles, and 6 orange marbles. After the first marble is drawn, it is not replaced. WHat is the probability that both marbles will be the same color? I know the formula looks something like (6*4*2)/(***)=

Answer 15

@kropot72 ^^^

Answer 16

\[\large P(2\ yellow)=\frac{2}{12}\times\frac{1}{11}\]
\[\large P(2\ green)=\frac{4}{12}\times\frac{3}{11}\]
\[\large P(2\ orange)=\frac{6}{12}\times\frac{5}{11}\]
\[\large P(2\ same\ colour)=\frac{1}{132}(2+12+30)=you\ can\ calculate\]

Answer 17

0.333 ?

Answer 18

@kropot72 ^^

Answer 19

Yes, 0.33333. or 1/3.

Answer 20

THANK YOU SO MUCH

Answer 21

are you good with deviation? @kropot72

Answer 22

You're welcome :)

Answer 23

"are you good with deviation?"
Please post as new question.