Question

Write the rectangular equation x^3+y^2-2x+0 in polar form....??

Answer 1

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{\hspace1.5pt\bigstar}\color{#11c520}{\hspace{1.5pt}\bigstar}\\\large\bf {I~will~tag~some~users~that~may~be~able~to~help~you}\)

@jim_thompson5910 @bibby

Answer 2

\(\LARGE\cal\color{cyan}{No~Problem!}\\\bbox [10pt, magenta,border:5pt solid blue ]{\color{#00ffab}{\huge\cal ~\heartsuit sleepyjess\heartsuit}}\)

Answer 3

x^3+y^2-2x+0 is not an equation so there seems to be a typo

Answer 4

Question:
Write the rectangular equation x^3+y^2-2x+0 in polar form....??
A. r=2sin theta
B. r^2-2rsin theta =0
C. r= cos2 theta
D. r=2cos theta

Answer 5

an equation has an equal sign, but it's missing in x^3+y^2-2x+0

Answer 6

is it possible that the x^3 is really x^2 ?

Answer 7

x^2+y^2-2x=0

Answer 8

in terms of polar equations, how can we use x^2 + y^2 ?

ie, what is x^2 + y^2 equal to in terms of 'r' ?

Answer 9

Is the answer r=2cos theta

Answer 10

how are you getting that?

Answer 11

because
r²cos²θ + r²sin²θ - 2r.cos θ = 0
r² - 2r cos θ = 0
r² = 2r cos θ
r = 2 cos θ

Answer 12

yes you are correct, nice work

Answer 13

r^2cos^2theta+ r^2sin^2theta - 2r cos theta= 0

r^2 = 2rcos theta
r^2+ 2r cos theta
r = 2 cos theta

Answer 14

ok thanks a lot

Answer 15

np

Answer 16

can you please be able to help me with another problem...
I'm actually doing my review sheet and I have to take my final exam tomorrow

Answer 17

sure, one more

Answer 18

3 square root 27i

Answer 19

can you draw it out?

Answer 20

\[3\sqrt{27i}\]

Answer 21

thanks

Answer 22

you need to convert the 27i into polar form

Answer 23

so how would you do that?

Answer 24

abs0 + 27i = square root 0^2 + (27)^2 = 27

Answer 25

yes, so r = 27

what is theta?

Answer 26

I'm not sure

Answer 27

Can you please be able to tell me how to solve....